Compilation error: "expected primary-expression before ' '" when trying to specify argument type in a function call Asked 13 years, 5 months ago Modified 2 years, 11 months ago Viewed 227k times
When applying this strategy to the question case, then std::expected should be selected, unless the input string is already validated according to your design - so, then the errors in parsing are not expected - so: exceptions. But most probably errors will be not totally unexpected - so std::expected.
I had to solve this unary operator expected issue in remove_old_pkgs() of the helper script abk for Arch Sign Modules. See also 6.4 Bash Conditional Expressions
Actually, the best way to learn about std::expected is a funny talk by the (in)famous Andrei Alexandrescu: "Expect the Expected!" What std::expected is, and when it's used Here are three complementing explanations of what an std::expected<T, E> is: It is the return type of a function which is supposed to return a T value - but which may encounter some error, in which case it will return a ...
print 1 ^ IndentationError: expected an indented block It's quite hard to understand what is happening here, it seems that there is an indent block... But as I said, I've used tabs and spaces, and you should never do that. You can get some info here. Remove all tabs and replaces them by four spaces. And configure your editor to do that ...
It is expected of/from you to find the solution. Such rude behavior was not expected of/from you. I am quite sure that from is the correct usage in both cases, but of could be used in the firs...
